python如何绘制分布折线图？本篇文章小编给大家分享一下python绘制分布折线图代码示例，文章代码介绍的很详细，小编觉得挺不错的，现在分享给大家供大家参考，有需要的小伙伴们可以来看看。
用Python 绘制分布（折线）图，使用的是 plot（）函数。
一个简单的例子：
# encoding=utf-8
import matplotlib.pyplot as plt
from pylab import * # 支持中文
mpl.rcParams['font.sans-serif'] = ['SimHei']
# 'mentioned0cluster',
names = ['mentioned1cluster','mentioned2cluster', 'mentioned3cluster', 'mentioned4cluster', 'mentioned5cluster', 'mentioned6cluster', 'mentioned7cluster', 'mentioned8cluster', 'mentioned9cluster', 'mentioned10cluster']
x = range(len(names))
# y_0625 = [39266,56796,42996,24872,13849,8609,5331,1971,554,169,26]
y_0626_1=[4793,100,0,0,0,0,0,0,0,0]
# y_0626_2=[2622,203,0,0,0,0,0,0,0,0,0]
# plt.plot(x, y, 'ro-')
# plt.plot(x, y1, 'bo-')
# pl.xlim(-1, 11) # 限定横轴的范围
# pl.ylim(-1, 110) # 限定纵轴的范围
plt.plot(x, y_0626_1, marker='o', mec='r', mfc='w', label='HighRating:MentionedClusterNum Distribution')
# plt.plot(x, y_0626_2, marker='o', mec='r', mfc='w', label='LowRating:MentionedClusterNum Distribution')
# plt.plot(x, y1, marker='*', ms=10, label=u'y=x^3曲线图')
plt.legend() # 让图例生效
plt.xticks(x, names, rotation=45)
plt.margins(0)
plt.subplots_adjust(bottom=0.15)
# plt.xlabel(u"time(s)邻居") # X轴标签
plt.xlabel("clusters")
plt.ylabel("number of reviews") # Y轴标签
plt.title("A simple plot") # 标题
plt.show()
结果：
